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c语言不用api函数编写简易计算器 无限循环

时间:2024-10-14 10:21:26

1、#include<stdio.h>int main(){printf("\n*欢迎使用计算器*\n");jmp();}void erjinzhi(int a,int i,int s){int b=0;if(a<256*256*1024){for(;b<27;b++){if(a<<b&256*256*1024){printf("1");}else{printf("0");}}}else {printf("数据过大,重新输入");return jmp();}}void xiangjia(long a,long b){printf("\n%d+%d=%d\n",a,b,a+b);}void xiangjian(long a,long b){printf("\n%d-%d=%d\n",a,b,a-b);}voidxiangcheng(long a,long b){printf("\n%d*%d=%d\n",a,b,a*b);}void xiangchu(float a,float b){printf("\n%f÷ %f= %f\n",a,b,a/b);} char xx(){printf(" 输入错误,请重新输入运算符号!");}int xxx(){printf("输入2个数计算\n");}int jmp(){int a,b,i=1,n=1,s=2;char c;printf("\n选择运算符号!\n+ - * \\ 2进制(2) 退出(q)\n");scanf(" %c",&c);if(c==50){printf("输入1个十进制数变2进制\n");scanf("%d",&a);printf("\n%d的二进制为:\n",a);erjinzhi(a,i,s);return jmp();}else{if(c==43){xxx();scanf("%d",&a);scanf("%d",&b);xiangjia(a,b);return jmp();}elseif(c==45){xxx();scanf("%d",&a);scanf("%d",&b);xiangjian(a,b);return jmp();}elseif(c==42){xxx();scanf("%d",&a);scanf("%d",&b);xiangcheng(a,b);return jmp();}elseif(c==47){xxx();scanf("%d",&a);scanf("%d",&b);xiangchu(a,b);return jmp();}if(c==113){return 0;}elsexx();return jmp();}}

2、复制上面代码,新建一个txt文本 粘贴 ,最后改后缀名为 .c 或者.cpp

c语言不用api函数编写简易计算器 无限循环

3、用你的编译器打开即可 运行

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